|
||
GRE : Quantitative Comparison Problem
In a history class that consisted of 30 students, the number of seniors was 3 more than twice the number of juniors, and 3/10 of the students were neither juniors nor seniors. Column A : The number of juniors in the class Column B : 6 The number who were neither juniors nor seniors was 30 X 3/10 = 30 x 3/10 = 3 x 3 = 9 SO, the total number of juniors and the seniors is 30 – 9 = 21. If the number of juniors was x, it is given that the number if seniors was (2x + 3). SO, (2x + 3) + x = 21 = 3x + 3 = 21 = 3x = 21 – 3 = 3x = 18 = x = 6 So, the number of juniors in the class is 6. As per this information, A = B. So, C is the answer. This is the Quantitative Comparison Problem. Understand the basic mathematical principles behind this problem and other problems.
Go to The GRE-Model Questions Index
From Quantitative Comparison Problem-9 to HOME PAG
|
Follow These Links!
|
|
|