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GRE : Quantitative Comparison Problem
Y = 3X/4: X = 2Z/3 and Z = 20 Column A : Y Column B : 11 Since as per the information given, Z = 20 X = 2Z/3 = X = 2 x 20/3 = X = 40/3 Y = 3X/4 = Y = [3 x 40/3] / 4 = Y = 3 x [40/4x3] = Y = [3 x 40]/ 12 = Y = 120/12 = Y = 10. So, B is greater than A. So, the answer is B. This is the Quantitative Comparison Problem.Understand the basic mathematical principles behind this problem and other problems.
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